4x^2+4=340

Solution for 4x^2+4=340 equation:

4x^2+4=340

We move all terms to the left:

4x^2+4-(340)=0

We add all the numbers together, and all the variables

4x^2-336=0

a = 4; b = 0; c = -336;
Δ = b2-4ac
Δ = 02-4·4·(-336)
Δ = 5376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5376}=\sqrt{256*21}=\sqrt{256}*\sqrt{21}=16\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{21}}{2*4}=\frac{0-16\sqrt{21}}{8}
=-\frac{16\sqrt{21}}{8}
=-2\sqrt{21}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{21}}{2*4}=\frac{0+16\sqrt{21}}{8}
=\frac{16\sqrt{21}}{8}
=2\sqrt{21}
$